question

Find three ways to modify the code below to print exactly 20 '-' characters by changing or inserting one character.

For this question be sure to check out the hint

```
int i, n = 20;
```

for (i = 0; i < n; i--)

{

print("-");

}

For this question be sure to check out the hint

*before*the answer!
Here are a few common

Changing "n = 20" to "n = -20" will not work

Changing "i--" to "i++" doesn't satisfy the one character condition

Changing "i = 0" to "i = 40" will not work

Changing "i < n" to "i < -n" will not work

Don't view the answer before you have three modifications!

**incorrect**solutions.Changing "n = 20" to "n = -20" will not work

Changing "i--" to "i++" doesn't satisfy the one character condition

Changing "i = 0" to "i = 40" will not work

Changing "i < n" to "i < -n" will not work

Don't view the answer before you have three modifications!

Here are three solutions - if you come up with one not listed here, email me to add it!

First solution - change "

Second solution - Change "

Third solution - Change "

First solution - change "

`i < n`

" to "`-i < n`

":
```
```

int i, n = 20;

for (i = 0; **-**i < n; i--)

{

print("-");

}

Second solution - Change "

`i < n`

" to "`i + n`

":
```
```

int i, n = 20;

for (i = 0; i **+** n; i--)

{

print("-");

}

Third solution - Change "

`i--`

" to "`n--`

":
```
```

int i, n = 20;

for (i = 0; i < n; **n**--)

{

print("-");

}