Technical Interview Question of the Day (5/14/12)

question

Create a method that takes an integer ( >= 1 ) and returns "true" if the integer is even and "false" if odd. You cannot use any conditional operators or switch statements.

ex. isEven(22) returns true

ex 2. isEven(1) returns false

show hint

Modulus operator will come in handy.

show answer


				isEven(input)
					
    String[] types = {"true", "false"};
					
    print( types[input % 2] );

For this solution we take advantage of arrays and the modulus operator. An odd number mod 2 will result in 1, while an even number mod 2 will result in 0. Therefore accessing the correct value in the array to print out.

Thanks to subscriber Michael Carrano for pointing out a mistake!